Q 11-11-095JEE MainJEE Main 2023 (8 Apr, Shift 2)Easy
Work done by a Carnot engine operating between temperatures $127^\circ\text{C}$ and $27^\circ\text{C}$ is $2$ kJ. The amount of heat transferred to the engine by the reservoir is
Answer: (A) $8\ \text{kJ}$
$\eta=1-\dfrac{300}{400}=0.25$, so $Q_1=\dfrac W\eta=\dfrac{2}{0.25}=8$ kJ.
Solution by Sreeraj P, M.Sc Physics