Q 11-10-032NEETJEE MainEAMCET 2012 (Engineering)Medium
The power radiated by a black body is $P$ and it radiates maximum energy around the wavelength $\lambda_0$. If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength $\dfrac{\lambda_0}{2}$, the power radiated becomes
Answer: (B) $16P$
Wien's law: halving $\lambda_m$ doubles $T$. Stefan's law: $P \propto T^4$, so the power becomes $2^4 P = 16P$.
Solution by Sreeraj P, M.Sc Physics