Q 11-10-031NEETJEE MainEAMCET 2003 (Medical)Easy
A particular star (assuming it to be a black body) has a surface temperature of about $5 \times 10^4$ K. The wavelength in nanometres at which its radiation becomes maximum is ($b = 0.0029$ m K)
Answer: (B) $58$
Wien's law: $\lambda_m = \dfrac{b}{T} = \dfrac{0.0029}{5 \times 10^4} = 5.8 \times 10^{-8}$ m $= 58$ nm.
Solution by Sreeraj P, M.Sc Physics