Q 11-10-033NEETJEE MainEAMCET 2007 (Engineering)Easy
A black body radiates energy at the rate of $E$ watt/m$^2$ at a high temperature $T$ K. When the temperature is reduced to $\dfrac{T}{2}$ K, the radiant energy is
Answer: (D) $\dfrac{E}{16}$
$E \propto T^4$, so halving $T$ gives $\dfrac{E}{2^4} = \dfrac{E}{16}$.
Solution by Sreeraj P, M.Sc Physics