The temperature of a metallic sphere of radius $R$ is increased by a small amount $\Delta T$. If the linear coefficient of thermal expansion of the metal is $\alpha$, the approximate increase in the volume of the sphere is :
Answer: (C) $4\pi R^3 \alpha \Delta T$
Volume expansion coefficient $\gamma = 3\alpha$.
$$\Delta V = \gamma V \Delta T = 3\alpha \cdot \frac{4}{3}\pi R^3 \cdot \Delta T = 4\pi R^3 \alpha \Delta T$$
Solution by Sreeraj P, M.Sc Physics