Q 11-06-160JEE MainJEE Main 2021 (22 Jul, Shift 1)Easy
The position of the centre of mass of a uniform semi-circular wire of radius $R$ placed in $x$-$y$ plane with its centre at the origin and the line joining its ends as $x$-axis is given by $\left(0, \dfrac{xR}{\pi}\right)$. Then, the value of $|x|$ is ______.
Numerical value type. Enter your answer.
Answer: 2
For a semicircular wire the centre of mass lies on the axis of symmetry at $\dfrac{2R}{\pi}$ from the centre. So $|x| = 2$.
Solution by Sreeraj P, M.Sc Physics