Q 11-06-124JEE MainJEE Main 2023 (8 Apr, Shift 1)Easy
The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is $\dfrac1xMR^2$, where $R$ is the radius and $M$ is the mass of the semicircular ring. The value of $x$ will be ______.
Numerical value type. Enter your answer.
Answer: 1
Every element of the semicircular ring is at distance $R$ from the axis, so $I=MR^2$ and $x=1$.
Solution by Sreeraj P, M.Sc Physics