Q 11-06-047JEE MainJEE Main 2026 (6 Apr, Shift 2)Medium
Two identical bodies A and B of equal masses have initial velocities $\vec{v_1} = 4\hat{i}$ m/s and $\vec{v_2} = 4\hat{j}$ m/s respectively. The body A has acceleration $\vec{a_1} = 6\hat{i} + 6\hat{j}\ \text{m/s}^2$ while the acceleration of the other body B is zero. The centre of mass of the two bodies moves in ______ path.
Answer: (C) straight line
$\vec{v}_{cm} = \dfrac{4\hat{i} + 4\hat{j}}{2} = 2\hat{i} + 2\hat{j}$ and $\vec{a}_{cm} = \dfrac{6\hat{i} + 6\hat{j}}{2} = 3\hat{i} + 3\hat{j}$.
The acceleration is parallel to the initial velocity, so the centre of mass moves along a straight line.
Solution by Sreeraj P, M.Sc Physics