Q 11-06-041JEE MainMedium
A uniform disc of mass $4$ kg and radius $0.5$ m rolls without slipping on a level floor at $2$ m/s. Find its total kinetic energy in joules.
Numerical value type. Enter your answer.
Answer: 12
$$K = \frac{1}{2}mv^2\left(1 + \frac{k^2}{R^2}\right) = \frac{1}{2}(4)(4)\left(1 + \frac{1}{2}\right) = 12\ \text{J}$$
Solution by Sreeraj P, M.Sc Physics