Q 12-14-095JEE MainJEE Main 2023 (12 Apr, Shift 1)Easy
In an n-p-n common emitter (CE) transistor the collector current changes from $5\ \text{mA}$ to $16\ \text{mA}$ for the change in base current from $100\ \mu\text{A}$ to $200\ \mu\text{A}$, respectively. The current gain of transistor is ______.
Answer: (A) 110
$\beta=\dfrac{\Delta I_C}{\Delta I_B}=\dfrac{11\ \text{mA}}{100\ \mu\text{A}}=110$.
Solution by Sreeraj P, M.Sc Physics