Q 11-13-078JEE MainJEE Main 2023 (10 Apr, Shift 2)Easy
For a periodic motion represented by the equation $y=\sin\omega t+\cos\omega t$, the amplitude of the motion is
Answer: (D) $\sqrt2$
$y=\sqrt2\sin\left(\omega t+\dfrac\pi4\right)$, so the amplitude is $\sqrt2$.
Solution by Sreeraj P, M.Sc Physics