Q 11-13-080JEE MainJEE Main 2023 (11 Apr, Shift 1)Easy
The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement ($x$) starting from mean position to extreme position ($A$) is given by
Answer: (C) see figure
$KE=\tfrac12k(A^2-x^2)$: maximum at $x=0$, falling as a downward parabola to zero at $x=A$. Graph (3).
Solution by Sreeraj P, M.Sc Physics