Q 11-13-014NEETJEE MainTop questionMedium
In SHM of amplitude $A$, at what displacement from the mean position is the kinetic energy equal to the potential energy?
Answer: (D) $\dfrac{A}{\sqrt{2}}$
Concept. $U = \dfrac12kx^2$, $K = \dfrac12k(A^2 - x^2)$.
Step 1. Equate. $x^2 = A^2 - x^2 \Rightarrow x = \dfrac{A}{\sqrt2}$.
Answer. $\dfrac{A}{\sqrt2}$ (Option D).
Solution by Sreeraj P, M.Sc Physics