Q 11-13-013NEETJEE MainEasy
The maximum speed and maximum acceleration of a particle in SHM are $4$ m/s and $16\ \text{m/s}^2$. Its amplitude is
Answer: (C) $1$ m
$v_{max} = A\omega$ and $a_{max} = A\omega^2$, so $\omega = \dfrac{a_{max}}{v_{max}} = 4$ rad/s and $A = \dfrac{v_{max}}{\omega} = 1$ m.
Solution by Sreeraj P, M.Sc Physics