Q 11-13-012NEETJEE MainEasy
A particle in SHM has amplitude $10$ cm and period $2$ s. Its speed when it is $6$ cm from the mean position is
Answer: (B) $8\pi$ cm/s
Concept. $v = \omega\sqrt{A^2 - x^2}$.
Step 1. Angular frequency. $\omega = \dfrac{2\pi}{2} = \pi$ rad/s.
Step 2. Speed. $v = \pi\sqrt{100 - 36} = 8\pi$ cm/s.
Answer. $8\pi$ cm/s (Option B).
Solution by Sreeraj P, M.Sc Physics