Q 11-13-012NEETJEE MainEasy
A particle in SHM has amplitude $10$ cm and period $2$ s. Its speed when it is $6$ cm from the mean position is
Answer: (B) $8\pi$ cm/s
$\omega = \dfrac{2\pi}{T} = \pi$ rad/s.
$$v = \omega\sqrt{A^2 - x^2} = \pi\sqrt{100 - 36} = 8\pi\ \text{cm/s}$$
Solution by Sreeraj P, M.Sc Physics