Q 11-13-020NEETJEE MainMedium
A mass on a spring oscillates with period $T$. The spring is cut into two equal halves and the same mass is attached to one half. The new period is
Answer: (B) $\dfrac{T}{\sqrt{2}}$
Each half has twice the force constant: $k' = 2k$. $T \propto \dfrac{1}{\sqrt{k}}$, so $T' = \dfrac{T}{\sqrt{2}}$.
Solution by Sreeraj P, M.Sc Physics