Q 11-13-026NEETJEE MainEasy
If the length of a simple pendulum is increased by $44\%$, its period increases by
Answer: (D) $20\%$
$T \propto \sqrt{l}$: $\dfrac{T'}{T} = \sqrt{1.44} = 1.2$, an increase of $20\%$.
Solution by Sreeraj P, M.Sc Physics