Q 11-13-027NEETJEE MainEasy
A pendulum clock keeps correct time on the Earth. On the Moon, where $g$ is $\dfrac{1}{6}$ of its value on Earth, the period of its pendulum becomes
Answer: (A) $\sqrt{6}$ times
$T \propto \dfrac{1}{\sqrt{g}}$, so $T_{moon} = \sqrt{6}\,T_{earth}$ and the clock runs slow.
Solution by Sreeraj P, M.Sc Physics