Q 11-13-027NEETJEE MainEasy
A pendulum clock keeps correct time on the Earth. On the Moon, where $g$ is $\dfrac{1}{6}$ of its value on Earth, the period of its pendulum becomes
Answer: (A) $\sqrt{6}$ times
Concept. $T \propto \dfrac{1}{\sqrt g}$.
Step 1. On the Moon. $g \to \dfrac{g}{6}$, so $T \to \sqrt6\,T$ (the clock runs slow).
Answer. $\sqrt6$ times (Option A).
Solution by Sreeraj P, M.Sc Physics