Q 11-13-032NEETJEE MainMedium
The acceleration of a particle is related to its displacement by $a = -16x$ (SI units). If its maximum displacement is $0.5$ m, its maximum speed is
Answer: (B) $2$ m/s
Concept. $a = -\omega^2x$ gives $\omega$; $v_{\max} = A\omega$.
Step 1. Angular frequency. $\omega^2 = 16 \Rightarrow \omega = 4$ rad/s.
Step 2. Maximum speed. $0.5 \times 4 = 2$ m/s.
Answer. $2$ m/s (Option B).
Solution by Sreeraj P, M.Sc Physics