Q 11-13-032NEETJEE MainMedium
The acceleration of a particle is related to its displacement by $a = -16x$ (SI units). If its maximum displacement is $0.5$ m, its maximum speed is
Answer: (B) $2$ m/s
$a = -\omega^2x$ gives $\omega = 4$ rad/s. $v_{max} = A\omega = 0.5 \times 4 = 2$ m/s.
Solution by Sreeraj P, M.Sc Physics