Q 11-13-035JEE MainMedium
A $0.2$ kg block on a spring of force constant $80$ N/m oscillates with amplitude $5$ cm. Find the maximum speed of the block, in m/s.
Numerical value type. Enter your answer.
Answer: 1
Concept. $v_{\max} = A\omega$ with $\omega = \sqrt{\dfrac{k}{m}}$.
Step 1. Angular frequency. $\omega = \sqrt{400} = 20$ rad/s.
Step 2. Maximum speed. $0.05 \times 20 = 1$ m/s.
Answer. $1$.
Solution by Sreeraj P, M.Sc Physics