Q 11-13-004NEETNEET 2025Top questionEasy
Two identical point masses P and Q, suspended from two separate massless springs of spring constants $k_1$ and $k_2$, respectively, oscillate vertically. If their maximum speeds are the same, the ratio ($A_Q/A_P$) of the amplitude $A_Q$ of mass $Q$ to the amplitude $A_P$ of mass $P$ is:
Answer: (D) $\sqrt{\dfrac{k_1}{k_2}}$
$v_{max} = A\omega = A\sqrt{\dfrac{k}{m}}$. With equal masses and equal $v_{max}$:
$$A_P\sqrt{k_1} = A_Q\sqrt{k_2} \;\Rightarrow\; \frac{A_Q}{A_P} = \sqrt{\frac{k_1}{k_2}}$$
Solution by Sreeraj P, M.Sc Physics