Q 11-13-009NEETNEET 2021Top questionEasy
A spring is stretched by $5$ cm by a force $10$ N. The time period of the oscillations when a mass of $2$ kg is suspended by it is :
Answer: (A) $0.628$ s
Concept. $k = \dfrac{F}{x}$ and $T = 2\pi\sqrt{\dfrac{m}{k}}$.
Step 1. Spring constant. $k = \dfrac{10}{0.05} = 200$ N/m.
Step 2. Period. $T = 2\pi\sqrt{\dfrac{2}{200}} = \dfrac{2\pi}{10} = 0.628$ s.
Answer. $0.628$ s (Option A).
Solution by Sreeraj P, M.Sc Physics