Q 11-13-008NEETNEET 2021Top questionEasy
A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is :
Answer: (C) $2$n
Concept. $U = \dfrac12kx^2$ with $x = A\sin\omega t$.
Step 1. Rewrite.
$$U = \frac12kA^2\sin^2\omega t = \frac14kA^2(1 - \cos2\omega t)$$
Step 2. Frequency. $U$ varies at $2\omega$, i.e. frequency $2n$.
Answer. $2$n (Option C).
Solution by Sreeraj P, M.Sc Physics