Nuclei question for JEE Main (JEE Main 2024 (4 Apr, Shift 2)), with solution

The disintegration energy $Q$ for the nuclear fission of ${}^{235}\text{U} \rightarrow {}^{140}\text{Ce} + {}^{94}\text{Zr} + n$ is ______ MeV. Given atomic masses of ${}^{235}\text{U}: 235.0439\,u$; ${}^{140}\text{Ce}: 139.9054\,u$; ${}^{94}\text{Zr}: 93.9063\,u$; $n: 1.0086\,u$. Value of $c^2 = 931\ \text{MeV/u}$.