Q 12-13-047JEE MainJEE Main 2024 (27 Jan, Shift 2)Medium
The atomic mass of $^{12}_{6}\text{C}$ is $12.000000\ \text{u}$ and that of $^{13}_{6}\text{C}$ is $13.003354\ \text{u}$. The required energy to remove a neutron from $^{13}_{6}\text{C}$, if mass of neutron is $1.008665\ \text{u}$, will be:
Answer: (C) $4.95\ \text{MeV}$
$^{13}_6\text{C} \to\, ^{12}_6\text{C} + n$. The mass that must be supplied:
$$\Delta m = (12.000000 + 1.008665) - 13.003354 = 0.005311\ \text{u}$$
$$E = 0.005311\times931.5 \approx 4.95\ \text{MeV}$$
Solution by Sreeraj P, M.Sc Physics