Q 12-13-005NEETNEET 2021Top questionMedium
The half-life of a radioactive nuclide is $100$ hours. The fraction of original activity that will remain after $150$ hours would be :
Answer: (C) $\dfrac{1}{2\sqrt{2}}$
$150$ hours is $1.5$ half-lives:
$$\frac{A}{A_0} = \left(\frac{1}{2}\right)^{150/100} = \left(\frac{1}{2}\right)^{3/2} = \frac{1}{2\sqrt{2}}$$
Solution by Sreeraj P, M.Sc Physics