Q 12-13-011JEE MainAIEEE 2006Easy
When $_3\text{Li}^7$ nuclei are bombarded by protons, and the resultant nuclei are $_4\text{Be}^8$, the emitted particles will be
Answer: (C) gamma photons
Concept. Mass number and charge are conserved; the emitted particle carries whatever is left over.
Step 1. Reaction. $^7_3\text{Li} + {}^1_1\text{p} \to {}^8_4\text{Be} + X$.
Step 2. Balance. Mass number: $8 = 8 + A \Rightarrow A = 0$. Charge: $4 = 4 + Z \Rightarrow Z = 0$.
Step 3. Identify. No mass number and no charge: a gamma photon.
Answer. Gamma photons (Option C).
Solution by Sreeraj P, M.Sc Physics
