Q 12-13-011JEE MainAIEEE 2006Easy
When $_3\text{Li}^7$ nuclei are bombarded by protons, and the resultant nuclei are $_4\text{Be}^8$, the emitted particles will be
Answer: (C) gamma photons
$^7_3\text{Li} + ^1_1\text{p} \to ^8_4\text{Be} + X$. Mass number: $8 = 8 + A$, so $A = 0$; charge: $4 = 4 + Z$, so $Z = 0$. A particle with no mass number and no charge is a gamma photon.
Solution by Sreeraj P, M.Sc Physics