Q 12-13-008NEETNEET 2020Top questionEasy
When a uranium isotope $^{235}_{92}\text{U}$ is bombarded with a neutron, it generates $^{89}_{36}\text{Kr}$, three neutrons and :
Answer: (A) $^{144}_{56}\text{Ba}$
$$^{235}_{92}\text{U} + {}^1_0n \rightarrow {}^{89}_{36}\text{Kr} + 3\,{}^1_0n + {}^A_ZX$$
Mass number: $236 = 89 + 3 + A$, so $A = 144$.
Atomic number: $92 = 36 + Z$, so $Z = 56$ (barium).
The product is $^{144}_{56}\text{Ba}$.
Solution by Sreeraj P, M.Sc Physics