Q 12-13-002NEETNEET 2024Top questionMedium
$$^{290}_{82}X \xrightarrow{\ \alpha\ } Y \xrightarrow{\ e^+\ } Z \xrightarrow{\ \beta^-\ } P \xrightarrow{\ e^-\ } Q$$
In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are :
Answer: (B) $286,\ 81$
Alpha emission: $A \to A - 4$, $Z \to Z - 2$. Positron ($e^+$) emission: $Z \to Z - 1$. Beta-minus ($\beta^-$, same as $e^-$) emission: $Z \to Z + 1$. The mass number does not change in beta decays.
$X\ (290, 82) \xrightarrow{\alpha} Y\ (286, 80) \xrightarrow{e^+} Z\ (286, 79) \xrightarrow{\beta^-} P\ (286, 80) \xrightarrow{e^-} Q\ (286, 81)$
Mass number $286$, atomic number $81$.
Solution by Sreeraj P, M.Sc Physics