Q 11-03-091JEE MainJEE Main 2023 (25 Jan, Shift 2)Easy
Two objects are projected with same velocity $u$ however at different angles $\alpha$ and $\beta$ with the horizontal. If $\alpha+\beta=90^\circ$, the ratio of horizontal range of the first object to the $2^\text{nd}$ object will be
Answer: (D) $1:1$
$R=\dfrac{u^2\sin2\theta}{g}$ and $\sin2\alpha=\sin(180^\circ-2\alpha)=\sin2\beta$. The ranges are equal: $1:1$.
Solution by Sreeraj P, M.Sc Physics