Q 11-03-093JEE MainJEE Main 2023 (10 Apr, Shift 2)Easy
Two projectiles are projected at $30^\circ$ and $60^\circ$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is
Answer: (D) $1:3$
$H\propto\sin^2\theta$: $\dfrac{\sin^230^\circ}{\sin^260^\circ}=\dfrac{1/4}{3/4}=1:3$.
Solution by Sreeraj P, M.Sc Physics