Q 11-03-037NEETJEE MainEasy
Two stones are thrown horizontally in opposite directions from the top of an $80$ m tall tower, with speeds $15$ m/s and $25$ m/s. The distance between the points where they land is ($g = 10\ \text{m/s}^2$)
Answer: (B) $160$ m
Both fall for the same time: $t = \sqrt{\dfrac{2 \times 80}{10}} = 4$ s.
They move apart at $15 + 25 = 40$ m/s horizontally, so the separation is $40 \times 4 = 160$ m.
Solution by Sreeraj P, M.Sc Physics