Q 11-03-040NEETJEE MainEasy
A wheel of radius $0.5$ m rotates uniformly at $300$ revolutions per minute. The centripetal acceleration of a point on its rim is
Answer: (A) $50\pi^2\ \text{m/s}^2$
Concept. $a_c = \omega^2r$.
Step 1. Angular speed. $\omega = 2\pi \times 5 = 10\pi$ rad/s.
Step 2. Acceleration. $100\pi^2 \times 0.5 = 50\pi^2\ \text{m/s}^2$.
Answer. $50\pi^2\ \text{m/s}^2$ (Option A).
Solution by Sreeraj P, M.Sc Physics