Q 11-09-064JEE MainJEE Main 2024 (6 Apr, Shift 2)Easy
The pressure inside a soap bubble is greater than the pressure outside by an amount (given: $R$ = radius of bubble, $S$ = surface tension of the soap solution)
Answer: (D) $\dfrac{4S}{R}$
A soap bubble has two surfaces, each giving $\dfrac{2S}{R}$, so the excess pressure is $\dfrac{4S}{R}$.
Solution by Sreeraj P, M.Sc Physics