Q 12-05-010NEETJEE MainEasy
A bar magnet of length $10$ cm and pole strength $2$ A m is cut into two equal halves perpendicular to its length. The magnetic moment of each half is
Answer: (A) $0.1\ \text{A m}^2$
Cutting perpendicular to the length keeps the pole strength and halves the length: $M = 2 \times 0.05 = 0.1\ \text{A m}^2$ (half the original $0.2$).
Solution by Sreeraj P, M.Sc Physics