Q 12-05-014NEETJEE MainMedium
A circular coil of $100$ turns and radius $5$ cm carries a current of $2$ A. Its magnetic moment is
Answer: (A) $0.5\pi\ \text{A m}^2$
$M = NIA = 100 \times 2 \times \pi(0.05)^2 = 0.5\pi\ \text{A m}^2 \approx 1.57\ \text{A m}^2$.
Solution by Sreeraj P, M.Sc Physics