Q 12-05-012NEETJEE MainEasy
A bar magnet of moment $2\ \text{A m}^2$ is placed at $30°$ to a uniform field of $0.3$ T. The torque on it is
Answer: (C) $0.3$ N m
Concept. Torque on a magnetic dipole: $\tau = MB\sin\theta$.
Step 1. Substitute.
$$\tau = 2 \times 0.3 \times \sin 30° = 2 \times 0.3 \times 0.5 = 0.3\ \text{N m}$$
Answer. $0.3$ N m (Option C).
Solution by Sreeraj P, M.Sc Physics