Q 11-12-070JEE MainJEE Main 2023 (13 Apr, Shift 2)Easy
The mean free path of molecules of a certain gas at STP is $1500d$, where $d$ is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at $373\ \text{K}$ is approximately
Answer: (C) $2049d$
$\lambda=\dfrac{kT}{\sqrt2\pi d^2P}\propto T$ at constant pressure.
$$\lambda=1500d\times\frac{373}{273}\approx2049d$$
Solution by Sreeraj P, M.Sc Physics