Q 11-12-076JEE MainJEE Main 2023 (13 Apr, Shift 1)Easy
The rms speed of oxygen molecule in a vessel at particular temperature is $\left(1+\dfrac5x\right)^{1/2}v$, where $v$ is the average speed of the molecule. The value of $x$ will be (take $\pi=\frac{22}{7}$)
Answer: (C) 28
$\dfrac{v_{rms}}{v_{avg}}=\sqrt{\dfrac{3\pi}{8}}=\sqrt{\dfrac{33}{28}}=\sqrt{1+\dfrac5{28}}$, so $x=28$.
Solution by Sreeraj P, M.Sc Physics