Q 11-12-043JEE MainJEE Main 2024 (4 Apr, Shift 2)Easy
The translational degrees of freedom $(f_t)$ and rotational degrees of freedom $(f_r)$ of a $\text{CH}_4$ molecule are
Answer: (B) $f_t = 3$ and $f_r = 3$
$\text{CH}_4$ is a non-linear (tetrahedral) molecule: 3 translational and 3 rotational degrees of freedom.
Solution by Sreeraj P, M.Sc Physics