Q 11-12-031JEE MainJEE Main 2026 (4 Apr, Shift 1)Medium
One gas of $n_1$ mole of molecules at temperature $T_1$, volume $V_1$, and pressure $P_1$, and another gas of $n_2$ mole of molecules at temperature $T_2$, volume $V_2$, and pressure $P_2$, are mixed resulting in pressure $P$ and volume $V$ of the mixture. The temperature of the mixture is ______.
Answer: (B) $\dfrac{T_1T_2PV}{T_2P_1V_1 + T_1P_2V_2}$
Concept. Mixing conserves the number of moles: $\dfrac{P_1V_1}{T_1}+\dfrac{P_2V_2}{T_2}=\dfrac{PV}{T}$.
Step 1. Solve. $T=\dfrac{PV}{P_1V_1/T_1+P_2V_2/T_2}=\dfrac{T_1T_2PV}{T_2P_1V_1+T_1P_2V_2}$.
Answer. Option B.
Solution by Sreeraj P, M.Sc Physics
