Q 11-07-138JEE MainJEE Main 2021 (24 Feb, Shift 1)Easy
Consider two satellites $S_1$ and $S_2$ with periods of revolution 1 hr and 8 hr respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite $S_1$ to the angular velocity of satellite $S_2$ is:
Answer: (A) $8 : 1$
$\omega = \dfrac{2\pi}{T}$, so $\dfrac{\omega_1}{\omega_2} = \dfrac{T_2}{T_1} = \dfrac{8}{1}$.
Solution by Sreeraj P, M.Sc Physics