Q 11-07-100JEE MainJEE Main 2023 (11 Apr, Shift 2)Easy
If $V$ is the gravitational potential due to sphere of uniform density on its surface, then its value at the centre of sphere will be
Answer: (D) $\dfrac{3V}2$
Inside a uniform sphere $V(r)=-\dfrac{GM}{2R^3}(3R^2-r^2)$. At the centre $V_c=-\dfrac{3GM}{2R}=\dfrac32V$.
Solution by Sreeraj P, M.Sc Physics