Q 11-07-027NEETJEE MainEasy
The orbital radius of satellite B is $4$ times that of satellite A around the same planet. If A's period is $2$ hours, B's period is
Answer: (C) $16$ hours
Concept. Kepler's third law: $T \propto r^{3/2}$.
Step 1. Scale. $T_B = 2 \times 4^{3/2} = 16$ hours.
Answer. $16$ hours (Option C).
Solution by Sreeraj P, M.Sc Physics