Q 11-07-027NEETJEE MainEasy
The orbital radius of satellite B is $4$ times that of satellite A around the same planet. If A's period is $2$ hours, B's period is
Answer: (C) $16$ hours
Kepler's third law: $T \propto r^{3/2}$:
$$T_B = 2 \times 4^{3/2} = 2 \times 8 = 16\ \text{hours}$$
Solution by Sreeraj P, M.Sc Physics