Q 11-07-031NEETJEE MainEasy
The escape velocity from the Earth is about $11.2$ km/s. The orbital speed of a satellite very close to the Earth's surface is about
Answer: (C) $7.9$ km/s
Concept. Near the surface $v_o = \sqrt{gR}$, $v_e = \sqrt{2gR}$.
Step 1. Ratio. $v_o = \dfrac{11.2}{\sqrt2} \approx 7.9$ km/s.
Answer. $7.9$ km/s (Option C).
Solution by Sreeraj P, M.Sc Physics