Q 11-07-026NEETJEE MainEasy
A satellite orbits the Earth at a height equal to the Earth's radius $R$. If $g$ is the acceleration due to gravity at the surface, its orbital speed is
Answer: (B) $\sqrt{\dfrac{gR}{2}}$
$$v = \sqrt{\frac{GM}{r}} = \sqrt{\frac{gR^2}{2R}} = \sqrt{\frac{gR}{2}}$$
Solution by Sreeraj P, M.Sc Physics