Q 11-07-024NEETJEE MainEasy
The acceleration due to gravity at a depth of $1600$ km below the Earth's surface is ($g = 9.8\ \text{m/s}^2$ at the surface, radius of Earth $= 6400$ km)
Answer: (D) $7.35\ \text{m/s}^2$
$$g_d = g\left(1 - \frac{d}{R}\right) = 9.8\left(1 - \frac{1600}{6400}\right) = 9.8 \times 0.75 = 7.35\ \text{m/s}^2$$
Solution by Sreeraj P, M.Sc Physics