Q 11-07-024NEETJEE MainEasy
The acceleration due to gravity at a depth of $1600$ km below the Earth's surface is ($g = 9.8\ \text{m/s}^2$ at the surface, radius of Earth $= 6400$ km)
Answer: (D) $7.35\ \text{m/s}^2$
Concept. $g_d = g\left(1 - \dfrac dR\right)$.
Step 1. Substitute. $9.8 \times 0.75 = 7.35\ \text{m/s}^2$.
Answer. $7.35\ \text{m/s}^2$ (Option D).
Solution by Sreeraj P, M.Sc Physics