Three capacitors of 2 μF, 3 μF and 6 μF are connected in series across a 12 V battery. The charge on each capacitor is

(D) 12 μC. (1)/(C) = (1)/(2) + (1)/(3) + (1)/(6) = 1, so C = 1 μF and Q = CV = 12 μC (the same on each in series).

Electrostatic Potential and Capacitance question for NEET / JEE Main, with solution

Q 12-02-031NEETJEE MainEasy

Three capacitors of $2\ \mu$F, $3\ \mu$F and $6\ \mu$F are connected in series across a $12$ V battery. The charge on each capacitor is