Q 12-02-037JEE MainJEE Main 2026 (6 Apr, Shift 2)Easy
The electric potential as a function of $x, y$ is given by $V = 5(x^2 - y^2)$ V. The electric field at a point $(2, 3)$ m is ______ V/m.
Answer: (A) $(-20\hat{i} + 30\hat{j})$
Concept. The field is the negative gradient of the potential: $E_x=-\dfrac{\partial V}{\partial x}$, $E_y=-\dfrac{\partial V}{\partial y}$.
Step 1. Components. $E_x=-10x$, $E_y=+10y$.
Step 2. At $(2,3)$. $\vec E=-20\hat i+30\hat j$ V/m.
Answer. Option A.
Solution by Sreeraj P, M.Sc Physics
