Q 12-02-026NEETJEE MainEasy
A parallel plate capacitor has plates of area $0.02\ \text{m}^2$ separated by $1$ mm of air. Its capacitance is ($\epsilon_0 = 8.85 \times 10^{-12}$ F/m)
Answer: (C) $177$ pF
$C = \dfrac{\epsilon_0A}{d} = \dfrac{8.85 \times 10^{-12} \times 0.02}{10^{-3}} = 1.77 \times 10^{-10}$ F $= 177$ pF.
Solution by Sreeraj P, M.Sc Physics